How do you solve the following system?: x +7y = 3 , 12x -9 y = 2x+7y=3,12x9y=2

1 Answer
Jun 25, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for xx:

x + 7y = 3x+7y=3

x + 7y - color(red)(7y) = 3 - color(red)(7y)x+7y7y=37y

x + 0 = 3 - 7yx+0=37y

x = 3 - 7yx=37y

Step 2) Substitute (3 - 7y)(37y) for xx in the second equation and solve for yy:

12x - 9y = 212x9y=2 becomes:

12(3 - 7y) - 9y = 212(37y)9y=2

(12 xx 3) - (12 xx 7y) - 9y = 2(12×3)(12×7y)9y=2

36 - 84y - 9y = 23684y9y=2

36 + (-84 - 9)y = 236+(849)y=2

36 + (-93)y = 236+(93)y=2

36 - 93y = 23693y=2

36 - color(red)(36) - 93y = 2 - color(red)(36)363693y=236

0 - 93y = -34093y=34

-93y = -3493y=34

(-93y)/color(red)(-93) = -34/color(red)(-93)93y93=3493

(color(red)(cancel(color(black)(-93)))y)/cancel(color(red)(-93)) = 34/93

y = 34/93

Step 3) Substitute 34/93 for y in the solution to the first equation at the end of Step 1 and calculate x:

x = 3 - 7y becomes:

x = 3 - (7 xx 34/93)

x = (93/93 xx 3) - 238/93

x = 279/93 - 238/93

x = 41/93

The Solution Is:

x = 41/93 and y = 34/93

Or

(41/93, 34/93)