How do you solve the following system?: $x + y =1 ,2x-y=-2$

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Answer 1 · 2015-12-07T12:41:57

$x+y=1$ (Consider this equation as equation 1)
$2x−y=−2$ (Consider this equation as equation 2)

Adding equation 1 & 2 we get
$3x=-1$
This implies $x=-1/3$
Substitute this in equation 1
$-1/3+y=1$
$y=1+1/3$
$y=3+1/3$
$y=4/3$

How do you solve the following system?: x + y =1 ,2x-y=-2x + y =1 ,2x-y=-2