# How do you solve the following system?: x + y =1 ,2x-y=-2

Dec 7, 2015

$x + y = 1$ (Consider this equation as equation 1)
2x−y=−2 (Consider this equation as equation 2)

Adding equation 1 & 2 we get
$3 x = - 1$
This implies $x = - \frac{1}{3}$
Substitute this in equation 1
$- \frac{1}{3} + y = 1$
$y = 1 + \frac{1}{3}$
$y = 3 + \frac{1}{3}$
$y = \frac{4}{3}$