How do you solve the following system?: #y=2x + 3 , y=-x + 12 #

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Answer 1 · 2016-04-18T16:50:59

#color(blue)(x=3#
#color(blue)(y =9#

#y = 2x + 3#.............equation #(1)#

#color(blue)(y = - x +12#.........equation #(2)#

Solving by substitution.
Substituting equation #2# in #1#:

#y = 2x + 3#

#color(blue)(- x +12)= 2x + 3#

#12 - 3= 2x + x#

#9= 3x#

#x = 9/3#

#color(blue)(x=3#

Finding #y# from equation #1#:
#y = 2x + 3#

#y = 2 * color(blue)((3)) + 3#

#y =6 + 3#

#color(blue)(y =9#