How do you solve the following system: #y = 3x – 12, 2x – 4y = 8#? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Özgür Özer Dec 30, 2015 #x=4#, #y=0# Explanation: #color(white)xxy=3x-12,2x-4y=8# #color(white)xx2x-4y=8<=>y=(x-4)/2# #=>color(red)(3x-12)=(x-4)/2# #=>color(blue)(x-4)=(x-4)/2# #=>x-4=0# #=>x-4color(green)(+4)=0color(green)(+4)# #=>x=4# #=>y=(color(red)4-4)/2# #=>y=0# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 1230 views around the world You can reuse this answer Creative Commons License