How do you solve the following system: $y = 4 x + 4, 5 x - 2 y = - 26$ $y=4x+4, 5x-2y=-26$ ?

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How do you solve the following system: $y = 4 x + 4, 5 x - 2 y = - 26$ $y=4x+4, 5x-2y=-26$ ?

1 Answer

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Answer 1 · 2018-06-02T06:32:10

$y = 28$ $y=28$
$x = 6$ $x=6$

Explanation:

$y = 4 x + 4$ $y=4x+4$ --- (1)
$5 x - 2 y = - 26$ $5x-2y=-26$ --- (2)

Sub (1) into (2)

$5 x - 2 (4 x + 4) = - 26$ $5x-2(4x+4)=-26$
$5 x - 8 x - 8 = - 26$ $5x-8x-8=-26$
$- 3 x - 8 = - 26$ $-3x-8=-26$
$3 x = 18$ $3x=18$
$x = 6$ $x=6$ --- (3)

Sub (3) into (1)

$y = 4 (6) + 4$ $y=4(6)+4$
$y = 28$ $y=28$

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How do you solve the following system: $y = 4 x + 4, 5 x - 2 y = - 26$ $y=4x+4, 5x-2y=-26$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system: y=4x+4,5x−2y=−26y=4x+4, 5x-2y=-26 ?

1 Answer

Explanation:

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Impact of this question

How do you solve the following system: $y = 4 x + 4, 5 x - 2 y = - 26$ $y=4x+4, 5x-2y=-26$ ?