How do you solve the following system?: $y= x-6 , x + 2y = 3$

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Answer 1 · 2015-11-16T07:28:16

Use substitution to find: $x = 5$ , $y = -1$

The first equation gives us an expression for $y$ that we can substitute into the second equation:

$3 = x + 2y$

$= x + 2(x-6)$

$= x + 2x - 12$

$= 3x - 12$

Add $12$ to both ends to get:

$3x=15$

Divide both sides by $3$ to get:

$x = 5$

Then from the first equation:

$y = x - 6 = 5 - 6 = -1$

How do you solve the following system?: y= x-6 , x + 2y = 3 y= x-6 , x + 2y = 3