How do you solve the following system?: # y= x-6 , x + 2y = 3 #

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Answer 1 · 2015-11-16T07:28:16

Use substitution to find: #x = 5#, #y = -1#

The first equation gives us an expression for #y# that we can substitute into the second equation:

#3 = x + 2y#

#= x + 2(x-6)#

#= x + 2x - 12#

#= 3x - 12#

Add #12# to both ends to get:

#3x=15#

Divide both sides by #3# to get:

#x = 5#

Then from the first equation:

#y = x - 6 = 5 - 6 = -1#