How do you solve the linear equation x-y =12 and 2x+y=3 using the substitution method?
1 Answer
Jun 11, 2018
Explanation:
#x-y=12to(1)#
#2x+y=3to(2)#
#"from equation "(2)toy=3-2xto(3)#
#color(blue)"substitute "y=3-2x" into equation "(1)#
#x-(3-2x)=12#
#x-3+2x=12#
#"add 3 to both sides"#
#3x=15#
#"divide both sides by 3"#
#x=15/3=5#
#"substitute "x=5" into equation "(3)#
#y=3-10=-7#
#"point of intersection "=(5,-7)#
graph{(y+2x-3)(y-x+12)((x-5)^2+(y+7)^2-0.04)=0 [-20, 20, -10, 10]}
