# How do you solve the quadratic 25m^2-8=-7 using any method?

Sep 8, 2016

$m = \frac{1}{5} \mathmr{and} m = - \frac{1}{5}$

#### Explanation:

Usually you make a quadratic equation equal to 0 and then solve it by factoring, completing the square, or the formula.

However, this quadratic equation is a special case because it does not have an x-term.

Move the numbers to the right side to get:

$25 {m}^{2} = - 7 + 8 = 1$

$\frac{25 {m}^{2}}{25} = \frac{1}{25} \text{ } \leftarrow$ divide both sides by 25

${m}^{2} = \frac{1}{25} \text{ "larr}$find the square root of both sides

$m = \pm \sqrt{\frac{1}{25}}$

$m = \frac{1}{5} \mathmr{and} m = - \frac{1}{5}$