# How do you solve the quadratic 2n^2-5=-35 using any method?

Dec 31, 2016

$n = \pm \sqrt{15} i$

#### Explanation:

Solve $2 {n}^{2} - 5 = - 35$.

Add $5$ to both sides.

$2 {n}^{2} = - 30$

Divide both sides by $2$.

${n}^{2} = - \frac{30}{2}$

${n}^{2} = - 15$

Take the square root of both sides.

$n = \pm \sqrt{- 15}$

$n = \pm \sqrt{15} i$