How do you solve the quadratic #2n^2-5=-35# using any method?

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Answer 1 · 2016-12-31T05:57:07

#n=+-sqrt(15)i#

Solve #2n^2-5=-35#.

Add #5# to both sides.

#2n^2=-30#

Divide both sides by #2#.

#n^2=-30/2#

#n^2=-15#

Take the square root of both sides.

#n=+-sqrt(-15)#

#n=+-sqrt(15)i#