How do you solve the quadratic $3 + \frac{1}{x} = \frac{10}{x^{2}}$ $3+1/x=10/x^2$ using any method?

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Answer 1 · 2016-12-07T08:12:15

$x = - 2$ $x= -2$ or $+ \frac{5}{3}$ $+5/3$

$3 + \frac{1}{x} = \frac{10}{x^{2}}$ $3+1/x=10/x^2$

Multiply through by $x^{2} \to 3 x^{2} + x = 10$ $x^2 -> 3x^2+x=10$

$3 x^{2} + x - 10 = 0$ $3x^2+x-10=0$

$(x + 2) (3 x - 5) = 0$ $(x+2)(3x-5)=0$

$x =$ $x=$ either $- 2$ $-2$ or $+ \frac{5}{3}$ $+5/3$

How do you solve the quadratic 3+1x=10x23+1/x=10/x^2 using any method?