How do you solve the quadratic 4-1/x=3/x^2 using any method?

1 Answer
Dec 27, 2016

Get rid of the denominators by multiplying the whole equation by color(blue)(x^2)

4 color(blue)( xx x^2) - 1/x color(blue)(xx x^2) = 3/x^2 color(blue)(xx x^2)

4x^2 -x = 3" "larr make equal to 0

4x^2 -x-3 =0

Find factors of 4 and 3 which subtract to give 1.

(4x+3)(x-1) =0" "larr either factor could be =0

If 4x+3 = 0" "rarr 4x=-3" "rarr x = -3/4

Ifx-1=0" " x = 1