How do you solve the quadratic $4 n^{2} + 1 = 157$ $4n^2+1=157$ using any method?

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Answer 1 · 2016-11-27T00:52:00

$n = \pm \sqrt{39}$ $n=+-sqrt39$

$4 n^{2} + 1 = 157$ $4n^2+1=157$

Subtract 1 from each side:
$4 n^{2} = 156$ $4n^2=156$

Divide each side by 4:
$n^{2} = 39$ $n^2=39$

Finally, square root each side:
$n = \pm \sqrt{39}$ $n=+-sqrt39$

How do you solve the quadratic 4n^2+1=1574n2+1=1574n^2+1=157 using any method?