How do you solve the quadratic 9n^2-5=-99 using any method?

Nov 25, 2016

$n = \pm \frac{\sqrt{94} i}{3}$

Explanation:

$9 {n}^{2} - 5 = - 99$

$9 {n}^{2} = - 94$

${n}^{2} = - \frac{94}{9}$

$n = \pm \sqrt{- \frac{94}{9}}$

$n = \pm \frac{\sqrt{94} i}{3}$