How do you solve the quadratic $9x^2+8=-35$ using any method?

Question

1679 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-21T14:26:09

$x=+-sqrt(43)/3i$

$9x^2+8=-35$

$9x^2 = -43$

$x^2 = -43/9$

$x =+- sqrt(-43/9) = +-sqrt(43)/sqrt(9)i$

$x=+-sqrt(43)/3i$

How do you solve the quadratic 9x^2+8=-359x^2+8=-35 using any method?