How do you solve the quadratic $x^2+9x+20=0$ using any method?

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Answer 1 · 2016-08-17T18:09:28

$x=-4$ or $x=-5$

Note that $4+5=9$ and $4*5=20$

So: $0 = x^2+9x+20 = (x+4)(x+5)$

Hence zeros: $-4, -5$

How do you solve the quadratic x^2+9x+20=0x^2+9x+20=0 using any method?