How do you solve the quadratic $x^2+x=-1$ using any method?

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Answer 1 · 2016-08-14T23:27:16

$-1/2+-sqrt(3)/2i$

If you add $1$ to both sides, the equation becomes:

$x^2+x+1=0$

This is in the form $ax^2+bx+c = 0$ with $a = b = c = 1$ .

This has roots given by the quadratic formula:

$x = (-b+-sqrt(b^2-4ac))/(2a)$

$=(-1+-sqrt(1^2-4(1)(1)))/(2*1)$

$=(-1+-sqrt(-3))/2$

$=-1/2+-sqrt(3)/2i$

How do you solve the quadratic x^2+x=-1x^2+x=-1 using any method?