How do you solve the simultaneous equations 4x + 6y = 164x+6y=16 and x + 2y = 5x+2y=5?

2 Answers
Jul 26, 2015

I found:
x=1x=1
y=2y=2

Explanation:

You can try multiplying the second equation by -33 and then add the two equations ogether (in column):
{4x+6y=16{4x+6y=16
{color(red)(-3x-6y=-15{3x6y=15 add:
x+0=1x+0=1
x=1x=1
Substitute into the first:
4*1+6y=1641+6y=16
6y=126y=12
y=12/6=2y=126=2

Jul 26, 2015

You can use the substitution method to solve this system of equations.

Explanation:

Your two equations look like this

{(4x + 6y = 16), (x + 2y = 5) :}

The first thing you need to do is use of the equations to solve for one of the two variables, x or y, then use this value into the other equation.

For simplicity, use the second equation to solve for x by adding -2y to both sides of the equation

x + color(red)(cancel(color(black)(2y))) - color(red)(cancel(color(black)(2y))) = 5 - 2y

x = 5 - 2y

Now plug this value for x in your first equation and solve for y

4 * (5 - 2y) + 6y = 16

20 - 8y + 6y = 16

20 - 2y = 16

Isolate y on one side of the equation

-2y + color(red)(cancel(color(black)(20))) - color(red)(cancel(color(black)(20))) = 16 - 20

-2y = -4 => y = (-4)/(-2) = 2

Now take this value and use it to determine x

x = 5 - 2y

x = 5 - 2 * 2 = 1

The two solutions to your system are

{(x = color(green)(1)), (y=color(green)(2)) :}