How do you solve the simultaneous equations y = 3x + 1 and 2x + y = 6?

Jul 21, 2015

I found:
$x = 1$
$y = 4$

Explanation:

You can substitute the first equation into the second for $y$:
you get:
$2 x + \textcolor{red}{3 x + 1} = 6$
$5 x = 5$
$x = \frac{5}{5} = 1$
substitute into the first equation:
$y = 3 + 1 = 4$