How do you solve the system $2x - 3y = 2-x$ and $3x - 2y = -2 + y$ ?

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Answer 1 · 2016-07-12T14:19:43

The soln. does not exist, or, the Soln. Set is $phi$ .

Given eqns. are $:2x-3y=2-x rArr 2x+x-3y=2rArr3x-3y=2.........(i)$

Similarly, from the second eqn., we have, $3x-3y=-2..........(ii)$

Substituting the value of $3x-3y$ from $(i)$ into $(ii)$ , we see that,

$2=-2$ , which is an impossible result.

Hence, the soln. does not exist, or, we can say that the Soln. Set is $phi$ .

How do you solve the system 2x - 3y = 2-x2x - 3y = 2-x and 3x - 2y = -2 + y3x - 2y = -2 + y?