How do you solve the system $2y+6=x$ and $y-3x=-13$ using substitution?

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Answer 1 · 2015-05-27T16:27:35

$2y+6=x$ ...............equation $(1)$

$y-3x=-13$
$y = -13 +3x$ ........equation $(2)$

substituting equation $(2)$ in equation $(1)$
$2y+6=x$
$2(-13 +3x) +6 = x$
$- 26 +6x +6 = x$
$6x -x = 20$
$x = 20/5 = 4$

substituting this value of $x$ in equation 2
$y = -13 +3x$
$y = -13 +3.(4)$
$y = -13 +12 = -1$

the solutions for the system of equations are
$color(purple)(x=4 and y =-1$

How do you solve the system 2y+6=x2y+6=x and y-3x=-13y-3x=-13 using substitution?