How do you solve the system #3x-2y=11# and #x-1/2y=4# using substitution?
1 Answer
Sep 5, 2017
Explanation:
#3x-2y=11to(1)#
#x-1/2y=4to(2)#
#"from "(2)color(white)(x)x=4+1/2yto(3)#
#"substitute "x=4+1/2y" into "(1)#
#3(4+1/2y)-2y=11#
#rArr12+3/2y-2y=11#
#rArr-1/2y=-1#
#rArry=2#
#"substitute this value into "(3)#
#rArrx=4+1=5#
#rArr"point of intersection "=(5,2)#
graph{(y-3/2x+11/2)(y-2x+8)((x-5)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}
