# How do you solve the system 3x + 4y = -2 and x = -2y?

We can substitue $x = - 2 y$ in the first equation:
$3 \left(- 2 y\right) + 4 y = - 2 \Rightarrow - 6 y + 4 y = - 2 \Rightarrow - 2 y = - 2 \Rightarrow$
$y = 1$ and than
$x = - 2$.