Question

How do you solve the system `3y=x-1` and `x-2y=2`?

Answer 1

In one of the equations you "translate" one into the other, then fill that in in the second equation.

`3x=x-1->x=3y+1`

`x-2y=2->(3y+1)-2y=2->y=1`

`x=3y+1=3*1+1=4`

Check!
`3y=x-1->3*1=4-1->3=3` check
`x-2y=2->4-2*1=2->2=2` check