How do you solve the system of equations #10x + 8y = 16# and #5y = 4x - 15#?

1 Answer
May 17, 2017

#x = 100/41#
#y = -43/41#

Explanation:

Given: #10x + 8y = 16 " and " 5y = 4x - 15#

Put both equations in the same form: #Ax + By = C# so that you can solve the system of equations using elimination.

#" "10x + 8y = 16 " and " 4x -5y = 15#

Find #x#:
To eliminate #y#, multiply the first equation by #5# and the second equation by #8#:

#" "50x + 40y = 80#
#ul(+32x - 40y = 120)#
#" "82x " " = 200#; #" "x = 200/82 = 100/41#

Find #y#:
Substitute #x# into either one of the equations and solve for #y#:

#10/1 * 100/41 + 8y = 16#

#1000/41 + 8y = 16#

#8y = 16/1 - 1000/41#

#8y = 656/41 - 1000/41 = -344/41#

#y = (-344/41)/8 = -344/41 * 1/8 = -43/41#