How do you solve the system of equations #12x = - 4y - 16# and #2x + 3y = 44#?

1 Answer
Nallasivam V
Aug 14, 2017

#y=20#
#x=-8#

Explanation:

Given -

#12x=-4y-16#
#2x+3y=44#

#12x+4y=-16#---------------(1)
#2x+3y=44# ---------------(2) #xx6#

#12x+4y=-16# ---------------(1)
#12x+18y=264#--------------(2)------- #(1)-(2)#
#-14y=-280#
#y=(-280)/(-14)=20#
#y=20#

Substitute #x=20# in equation (1)

#12x+4(20)=-16#
#12x+80=-16#
#12x=-16-80=-96#
#x=(-96)/12=-8#
#x=-8#

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