How do you solve the system of equations #2x+3y=105# and #x+2y=65#? Algebra Systems of Equations and Inequalities Systems Using Substitution 1 Answer Ssss · Stefan V. Apr 19, 2018 #x# equals #15# and #y# equals #25#. Explanation: Set the easiest equation to #x# (the last one) and because #x = -2y+65# the #x# in the other equation also equals that, you can replace the #x# in the first equation with the #-2y+65#. Then simplify and solve for the #y#. You can plug the #25# into either equation to simplify and solve for #x#. Looks like: #x=-2y+65# so #2(-2y+65)+3y=105# #-4y+3y=105-130# #y=25# And #x+2(25)=65# #x=15# Answer link Related questions How do you solve systems of equations using the substitution method? How do you check your solutions to a systems of equations using the substitution method? When is the substitution method easier to use? How do you know if a solution is "no solution" or "infinite" when using the substitution method? How do you solve #y=-6x-3# and #y=3# using the substitution method? How do you solve #12y-3x=-1# and #x-4y=1# using the substitution method? Which method do you use to solve the system of equations #y=1/4x-14# and #y=19/8x+7#? What are the 2 numbers if the sum is 70 and they differ by 11? How do you solve #x+y=5# and #3x+y=15# using the substitution method? What is the point of intersection of the lines #x+2y=4# and #-x-3y=-7#? See all questions in Systems Using Substitution Impact of this question 988 views around the world You can reuse this answer Creative Commons License