How do you solve the system of equations $2 x + 6 y = 3$ $2x + 6y = 3$ and $- 2 x + 14 y = 7$ $- 2x + 14y = 7$ ?

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How do you solve the system of equations $2 x + 6 y = 3$ $2x + 6y = 3$ and $- 2 x + 14 y = 7$ $- 2x + 14y = 7$ ?

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Answer 1 · 2018-04-14T12:34:43

$x = 0$ $x=0$
$y = \frac{1}{2}$ $y=1/2$

Explanation:

$2 x + 6 y = 3$ $2x+6y=3$ --- (1)
$- 2 x + 14 y = 7$ $-2x+14y=7$ --- (2)

From (1),
$2 x + 6 y = 3$ $2x+6y=3$
$2 x = 3 - 6 y$ $2x=3-6y$
$x = \frac{1}{2} (3 - 6 y)$ $x=1/2(3-6y)$ --- (3)

Sub (3) into (2)

$- 2 \times \frac{1}{2} (3 - 6 y) + 14 y = 7$ $-2times1/2(3-6y)+14y=7$
$6 y - 3 + 14 y = 7$ $6y-3+14y=7$
$20 y = 10$ $20y=10$
$y = \frac{1}{2}$ $y=1/2$ --- (4)

Sub (4) into (3)

$x = \frac{1}{2} (3 - 6 \times \frac{1}{2})$ $x=1/2(3-6times1/2)$
$x = 0$ $x=0$

Answer 2 · 2018-04-14T12:35:54

make x in terms of y and then substitute in the second equation

Explanation:

2 $x$ $x$ + $6 y$ $6y$ = 3

2 $x$ $x$ = 3 - 6 $y$ $y$

$x$ $x$ = $\frac{3}{2}$ $3/2$ - 3 $y$ $y$

substitute in the second equation

-2 $x$ $x$ + 14 $y$ $y$ = 7

-2( $\frac{3}{2}$ $3/2$ - 3 $y$ $y$ ) + 14 $y$ $y$ = 7

-3 + 6 $y$ $y$ +14 $y$ $y$ = 7
20 $y$ $y$ = 10

$y$ $y$ = $\frac{1}{2}$ $1/2$

then substitute y in any of the 2 equations to get x
you get $y$ $y$ = $\frac{1}{2}$ $1/2$ and $x$ $x$ = 0

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How do you solve the system of equations $2 x + 6 y = 3$ $2x + 6y = 3$ and $- 2 x + 14 y = 7$ $- 2x + 14y = 7$ ?

2 Answers

Explanation:

Explanation:

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How do you solve the system of equations $2 x + 6 y = 3$ $2x + 6y = 3$ and $- 2 x + 14 y = 7$ $- 2x + 14y = 7$ ?