How do you solve the system of equations #2x + 8y = 16# and #4x + 6y = - 8#?

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Answer 1 · 2018-04-15T18:05:28

#x=-8#
#y=4#

#2x+8y=16#
#4x+6y=-8#

We multiply the first one by (-2) and add it to the second one, so we can use the elimination method.

#-4x-16y=-32#
#color(red)cancel(4x)+6ycolor(red)cancel(-4x)-16y=-8-32#

#2x+8y=16#
#-10y=-40#

#2x+8y=16#
#y=4#

#2x+8*4=16#
#y=4#

#2x+32=16#
#y=4#

#2x=-16#
#y=4#

#x=-8#
#y=4#