How do you solve the system of equations $\frac{2 x}{y} = 12$ $(2x)/y=12$ and $8 (y + 2) = x$ $8(y+2)=x$ ?

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Answer 1 · 2016-10-12T20:36:59

$x = - 48$ $x=-48$

$y = - 8$ $y=-8$

$\frac{2 x}{y} = 12 (1)$ $(2x)/y=12 " (1)"$

$8 (y + 2) = x (2)$ $8(y+2)=x" (2)"$

$rearrange the equation (1)$ $"rearrange the equation (1)"$

$cancel(2)x=cancel(12)y$

$x=color(green)(6y)$

$"now use the equation (2)"$

$8(y+2)=color(green)(6y)$

$8y+16=6y$

$8y-6y=-16$

$2y=-16$

$y=-16/2$

$y=-8$

$"use (1)"$

$(2x)/-8=12$

$cancel(2)x=-cancel(8)*12$

$x=-48$

How do you solve the system of equations (2x)/y=122xy=12(2x)/y=12 and 8(y+2)=x8(y+2)=x8(y+2)=x?