How do you solve the system of equations 2x+y=3 and 3x-2y=8?

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#2x+y=3 , 3x-2y=8#

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Answer 1 · 2018-05-14T17:44:35

#x=2# and #y=-1#

show below

#2x+y=3#............1

#3x-2y=8#............2

from equation 1

#y=3-2x#..........3

now put 3 in 2

#3x-2(3-2x)=8#

#3x-6+4x=8#

#7x=14#

#x=2#

#y=3-2(2)=3-4=-1#