How do you solve the system of equations $2x-y+3z=-1$ , $x+2y-4z=-1$ and $y-2z=0$ by elimination?

Question

3628 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-07T17:23:21

From third equation $y=2z$

After plugging y into second one,

$x+2*2z-4z=-1$ or $x=-1$ .

After plugging x and y into first one,

$2*(-1)-2z+3z=-1$

$-2+z=-1$

$z=1$ . Consequently, $y=2*1=2$

1) I found y in terms of z from third equation.

2) I plugged y into second one for finding x.

3) I plugged x and y into first one for finding z.

4) I found y.

How do you solve the system of equations 2x-y+3z=-12x-y+3z=-1, x+2y-4z=-1x+2y-4z=-1 and y-2z=0y-2z=0 by elimination?