How do you solve the system of equations 2x+y=8 and 3xy=7?

1 Answer
Apr 11, 2018

See a solution process below:

Explanation:

Step 1) Solve the first equation for y:

2x+y=8

2x2x+y=82x

0+y=82x

y=82x

Step 2) Substitute (82x) for y in the second equation and solve for x:

3xy=7 becomes:

3x(82x)=7

3x8+2x=7

3x8+8+2x=7+8

3x0+2x=15

3x+2x=15

(3+2)x=15

5x=15

5x5=155

x=3

Step 3) Substitute 3 for x in the solution to the first equation at the end of Step 1 and calculate y:

y=82x becomes:

y=8(2×3)

y=86

y=2

**The Solution Is:

x=3 and y=2

Or

(3,2)