Question

How do you solve the system of equations `2y=x-2` and `3y-3/2x-3`?

Answer 1

Assuming that the second expression was meant to be the equation `3ycolor(red)=3/2x-3`
then the two equations are simply variations of the same thing, so infinitely many solutions are possible.

Explanation:

`2y=x-2color(white)("xxx")hArrcolor(white)("xxxx")2xx(color(blue)(y=x/2-1))`

`3y=3/2x-3color(white)("xxx")hArrcolor(white)("xxx")3xx(color(blue)(y=x/2-1))`

The given equations are colinnear and are in fact just variations of the linear equation which in standard form would be:
`color(white)("XXX")1x-2y=2`