How do you solve the system of equations: 3T-2S=0, T+2S=15?

Question

1026 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-08-22T08:01:40

The solutions are
#color(blue)(T=3.75, S=5.625#

#3T-color(blue)(2S)=0#
# T+color(blue)(2S)=15#

Solving by elimination

Adding both equations
#3T-cancelcolor(blue)(2S)=0#

# T+cancelcolor(blue)(2S)=15#
#4T=15#
#T=15/4#
#color(blue)(T=3.75#

Finding #S# from equation #1#
#3T-2S=0#

#3T=2S#

#S=(3T)/2#

#S=11.25/2#
#color(blue)(S=5.625#