How do you solve the system of equations #3x + 2y = 11# and #x - 2= - 4y#?

1 Answer
Apr 14, 2018

x = 4 , y = #-1/2#

Explanation:

1/ 3x + 2y = 11
x - 2 = -4y => x + 4y = 2
2/ Multiply -2 for the first equation to make y equal both side, then combine them.
=> -6x - 4y = -22
+ x + 4y = 2
=> -5x = -20 => x = 4
3/ Log in x = 4 for one of the equation to find y, you can choose which equation you want.
Eq 2: (4) + 4y = 2 => 4y = -2 => y = #-1/2#
You can check the answer by log in the value of x and y