How do you solve the system of equations #3x-2y=-21# and #2x+5y=5# by elimination?

1 Answer
Apr 30, 2016

You need to make the coefficients of either the #x# or the #y# the same. The better option is to have them with different signs. These are called additive inverses.

Explanation:

#3x# and #2x# can both be made into the LCM #6x#, by multiplying the whole of the first equation by 2 and the whole of the second equation by 3. You would then subtract one equation from the other to eliminate the #x# terms.

However, an easier method which will incur fewer errors is to make both the #y# terms into #10y#. Note that the signs are different.
Multiply the whole of the first equation by 5 and the whole of the second equation by 2. The following two equations will be obtained:

#15x-10y = -105#
# 4x+ 10y = 10#
When these two equations are added, the #y# terms are eliminated because they add to give zero. An equation will only one variable is formed .... #19x = -95#
which gives #x= -5#

Simple substitution into either of the original equations gives
#y=3#.

Check the answer by substituting the values #x = -5 and y = 3# into the other equation.