How do you solve the system of equations $3x + 2y = - 7$ and $2x - 7y = 37$ ?

Question

2194 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-15T05:38:44

$x=1$
$y=-5$

$3x+2y=-7$ --- (1)
$2x-7y=37$ --- (2)

From (1),

$3x+2y=-7$
$3x=-2y-7$
$x=1/3(-2y-7)$ --- (3)

Sub (3) into (2),

$2times1/3(-2y-7)-7y=37$

$2/3(-2y-7)-7y=37$

$-4/3y-14/3-7y=37$

$-25/3y=125/3$

$y=-5$ --- (4)

Sub (4) into (3),

$x=1/3(-2(-5)-7)$

$x=1/3(3)$

$x=1$

How do you solve the system of equations 3x + 2y = - 73x + 2y = - 7 and 2x - 7y = 372x - 7y = 37?