How do you solve the system of equations 3x + 3y = - 6 and x + 6y = - 32?

1 Answer
Jun 2, 2017

(4,-6)

Explanation:

First, we can simplify the first equation:

3x+3y = -6

(3x)/3 + (3y)/3 = (-6)/3

x+y = -2

Now, subtract the first equation from the second equation:

color(white)"X"x+6y = -32
-(x+y = -2)

color(white)"XXX-" 5y = -30

And solve for y:

(5y)/5 = (-30)/5

y = -6

Now that we know y, all we have to do is plug in -6 for y and solve for x.

x+y = -2

x-6=-2

color(white)"e"x = 4

So our solution is:

x=4,y=-6 color(white)"XX" or color(white)"XX" (4,-6)

Final Answer