How do you solve the system of equations 3x + 3y = - 6 and x + 6y = - 32?
1 Answer
Jun 2, 2017
Explanation:
First, we can simplify the first equation:
3x+3y = -6
(3x)/3 + (3y)/3 = (-6)/3
x+y = -2
Now, subtract the first equation from the second equation:
color(white)"X"x+6y = -32
-(x+y = -2)
color(white)"XXX-" 5y = -30
And solve for y:
(5y)/5 = (-30)/5
y = -6
Now that we know
x+y = -2
x-6=-2
color(white)"e"x = 4
So our solution is:
x=4,y=-6 color(white)"XX" orcolor(white)"XX" (4,-6)
Final Answer