How do you solve the system of equations #3x + 5y = 4# and #3x + 7y = 2#?

1 Answer
Dec 11, 2016

#x=3# and #y=-1#

Explanation:

#3x+5y=4#
#3x+7y=2#

From the first equation, we can determine a value for #3x#.

#3x+5y=4#

Subtract #5y# from both sides.

#3x=4-5y#

In the second equation, substitute #3x# with #color(red)((4-5y))#.

#3x+7y=2#

#color(red)((4-5y))+7y=2#

Open the brackets and simplify.

#color(red)(4-5y)+7y=2#

#4+2y=2#

Subtract #4# from each side.

#2y=-2#

Divide both sides by #2#.

#y=-1#

In the first equation, substitute #y# with #-1#.

#3x+5y=4#

#3x+5(-1)=4#

Open brackets and simplify.

#3x-5=4#

Add #5# to both sides.

#3x=9#

Divide both sides by #3#.

#x=3#