How do you solve the system of equations $3x + 7y = 49$ and $2x + 4y = 27$ ?

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Answer 1 · 2016-12-31T16:32:51

$y=27/2,x=-27/2$

$3x+7y=49$

$2x+4y=27$

$3x+7y=49----a$

$2x+4y=27----b$

$6x+14y=98----$ a * 2 $----c$

$6x+12y=71----b * 3----d$

$2y=27------c-d$

$y=27/2$

substitute $y=27/2$ in --------b

$2x+4(27/2)=27$

$2x+54=27$

$2x=27-54$

$2x=-27$

$x=-27/2$

substitute $y=27/2,x=-27/2$ in --------b

$2(-27/2)+4(27/2)=27$

$-27+54=27$

$27=27$

How do you solve the system of equations 3x + 7y = 493x + 7y = 49 and 2x + 4y = 272x + 4y = 27?