How do you solve the system of equations #-3x + 7y = - 9# and #- 2x + 10y = 10#?

1 Answer
Jan 27, 2018

See a solution process below:

Explanation:

Step 1) Solve each equation for #6x#:

-Equation 1:

#-3x + 7y = -9#

#-3x + 7y - color(red)(7y) = -9 - color(red)(7y)#

#-3x + 0 = -9 - 7y#

#-3x = -9 - 7y#

#color(red)(-2) xx -3x = color(red)(-2)(-9 - 7y)#

#6x = (color(red)(-2) xx -9) + (color(red)(-2) xx -7y)#

#6x = 18 + 14y#

-Equation 2:

#-2x + 10y = 10#

#-2x + 10y - color(red)(10y) = 10 - color(red)(10y)#

#-2x + 0 = 10 - 10y#

#-2x = 10 - 10y#

#color(red)(-3) xx -2x = color(red)(-3)(10 - 10y)#

#6x = (color(red)(-3) xx 10) + (color(red)(-3) xx -10y)#

#6x = -30 + 30y#

Step 2) Because the left side of both equations are equal we can equate the right side of each equation and solve for #y#:

#18 + 14y = -30 + 30y#

#18 + color(red)(30) + 14y - color(red)(14y) = -30 + color(red)(30) + 30y - color(red)(14y)#

#48 + 0 = 0 + 16y#

#48 = 16y#

#48/color(red)(16) = (16y)/color(red)(16)#

#3 = (color(red)(cancel(color(black)(16)))y)/cancel(color(red)(16))#

#3 = y#

#y = 3#

Step 3) Substitute #3# for #y# into either of the equations in Step 1 and solve for #x#:

#6x = -30 + 30y# becomes:

#6x = -30 + (30 xx 3)#

#6x = -30 + 90#

#6x = 60#

#(6x)/color(red)(6) = 60/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x)/cancel(color(red)(6)) = 10#

#x = 10#

The Solution Is:

#x = 10# and #y = 3#

Or

#(10, 3)#