How do you solve the system of equations #3x - y = - 10# and #x - y = 2# by elimination?

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Answer 1 · 2018-01-24T14:59:10

The solution set is #(-6,-8)#.

We've got #3x-y=-10#, and #x-y=2#

So now, we can take #x-y=2# as #y-x=-2#.

Now simply add the two equations:

#(3x-y)+(y-x)=-10+(-2)#

#2x=-12#

#x=-6#

So if #x=-6#, #y# can be found by substitution:

#3(-6)-y=-10#

#-18-y=-10#

#-y=8#

#y=-8#

So here, #x=-6, y=-8#, and the solution set is #(-6,-8)#.