How do you solve the system of equations #3x - y = 71# and #4y = x#?

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Answer 1 · 2017-01-27T19:06:53

See the entire solution process below:

Step 1) Because the second equation is already solved for #x# we can substitute #4y# for #x# in the first equation and solve for #y#:

#3(4y) - y = 71#

#12y - y = 71#

#11y = 71#

#(11y)/color(red)(11) = 71/color(red)(11)#

#y = 71/11#

Step 2) Substitute #71/11# for #y# in the second equation and calculate #x#:

#4 xx 71/11 = x#

#284/11 = x#

The solution is #x = 284/11# and #y = 71/11#