How do you solve the system of equations 4x - 2y = 14x2y=1 and 8x + 4y = 68x+4y=6?

1 Answer
Jun 14, 2018

x=1/2x=12 and y=1/2y=12

Explanation:

4x-2y=14x2y=1
8x+4y=68x+4y=6

Eliminate term xx to find yy by multiplying top equation by 88 and bottom equation by 44:

32x-16y=832x16y=8
32x+16y=2432x+16y=24

Subtract equations from each other:

-32y=-1632y=16
y=(-16)/-32y=1632
y=1/2y=12

Substitute y=1/2y=12 into one of the original equations and solve for xx:

4x-2y=14x2y=1
4x-2(1/2)=14x2(12)=1
4x-1=14x1=1
4x=24x=2
x=2/4x=24
x=1/2x=12