How do you solve the system of equations #4x - 2y = 1# and #8x + 4y = 6#?

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Answer 1 · 2018-06-14T12:36:12

#x=1/2# and #y=1/2#

#4x-2y=1#
#8x+4y=6#

Eliminate term #x# to find #y# by multiplying top equation by #8# and bottom equation by #4#:

#32x-16y=8#
#32x+16y=24#

Subtract equations from each other:

#-32y=-16#
#y=(-16)/-32#
#y=1/2#

Substitute #y=1/2# into one of the original equations and solve for #x#:

#4x-2y=1#
#4x-2(1/2)=1#
#4x-1=1#
#4x=2#
#x=2/4#
#x=1/2#