How do you solve the system of equations #4x-2y = 24# and #y = x-5# by substitution?

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Answer 1 · 2016-02-08T09:34:56

#x=7#
#y=2#

Given #4x-2y=24# and #y=x-5#
#4x-2y=24# 1st equation
#y=x-5# 2nd equation

Use the 2nd equation in place of the 1st

start with

#4x-2y=24#

#4x-2(x-5)=24# substitution

#4x-2x+10=24#

#2x=24-10#

#2x=14#

#(2x)/2=14/2#

#(cancel2x)/cancel2=14/2#

#x=7#

return to the 2nd equation use #x=7#

#y=x-5#

#y=7-5#

#y=2#

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