How do you solve the system of equations #4x + 3y = 8# and #3x - 3y = 6# using elimination?

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Answer 1 · 2017-03-22T06:20:48

#(2, 0)#

Since equation 1 has a #+3y# and equation 2 has a #-3y#, add the two equations to eliminate the #y#-variable.

#EQ. 1 + EQ. 2: #

#4x + 3x +3y -3y = 8+6;#

# 7x = 14#;

#x = 14/7 = 2#

To find #y#, put the #x = 2# into either equation and solve for #y#:

#4(2) +3y = 8#

#8 +3y = 8#

#8 - 8 + 3y = 8 - 8#

#3y = 0#

#y = 0#