How do you solve the system of equations -4x + 6y = 4 and - x + 8y = 1?
1 Answer
Explanation:
{(-4x + 6y = 4), (-x + 8y = 1) :}
{(-4x + 6y = 4), ( (-x + 8y = 1) * (-4)) :}
{(-4x + 6y = 4), (4x - 32y = -4) :}
Add these together to get
-26y = 0
Therefore
y=0
Plug
-x + (8 * 0) = 1
-x = 1
x = -1
Check your answer by putting
(-4 x -1) + (6 * 0) = 4
4 + 0 = 4
4 = 4
:)