# How do you solve the system of equations 6x - 2y = - 8 and 3x - y = - 4?

Mar 18, 2017

Solution below.

#### Explanation:

$1.$ Pick an equation and find $y$ in terms of $x$

$3 x - y = - 4$

$3 x = - 4 + y$

$3 x + 4 = y$

$2.$ Substitute the value for $y$ in the other equation

$y = 3 x - 4$

$6 x - 2 y = - 8$

$6 x - 2 \left(3 x + 4\right) = - 8$

$6 x - 6 x - 8 = - 8$

$- 8 = - 8$

Since $- 8$ is always equal to $- 8$, $x$ can be any real number. So the solution is infinite solutions.