How do you solve the system of equations #6x-4y=24# and #5x+10y=30# by elimination?

2 Answers
Aug 10, 2016

#x=9/2#
#y=3/4#

Explanation:

#6x-4y=24#
or
#2(3x-2y)=24#
or
#3x-2y=24/2#
or
#3x-2y=12#------------Eq.#A#

#5x+10y=30#
or
#5(x+2y)=30#
or
#x+2y=30/5#
or
#x+2y=6#--------------Eq. #B#
Adding up Eq.#A# and #B#
We get
#3x-2y+x+2y=12+6#
or
#4x+0=18#
or
#4x=18#
or
#x=18/4#
or
#x=9/2#----------------------Ans #1#
By putting the value #x=9/2# in the equation #x+2y=6#
We get
#9/2+2y=6#
or
#2y=6-9/2#
or
#2y=3/2#
or
#y=3/4#--------------------------Ans #2#

Aug 10, 2016

#x = 4 1/2, y = 3/4#

Explanation:

Neither of these equations is in simplest form. Let's do that first:

#6x-4y =24 " "div 2 rArr " "3x -2y = 12 .....................A#
#5x +10y = 30" "div 5 rArr" "x+2y = 6.......................B#

#color(white)(..............)3x color(red)(-2y) = 12 .....................A#
#color(white)(................)xcolor(red)(+2y) = 6.......................B#

#A+B color(white)(............)4x=18" "# (y-terms have been eliminated)

#color(white)(........................) x = 4 1/2#

Subst into B: #4 1/2 + 2y = 6#

#color(white)(................) 2y = 6- 4 1/2 = 1 1/2#

#color(white)(...................)y= 3/4#