How do you solve the system of equations #6x - 4y = 6# and #- 5x + 4y = - 9#?

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Answer 1 · 2016-11-06T15:00:50

#x=-3# and #y=-6#

#6x-4y=6#
#-5x+4y=-9#

Adding the two equations we get:

#x=-3#

Replacing #x# with #-3# in any equation we get the value of #y#.

#6(-3)-4y=6#

#-18-4y=6#

Add #18# to both sides.

#-4y=24#

Divide both sides by 4 and change signs.

#-y=6# or #y=-6#